2x^2+95x-3000=0

Solution for 2x^2+95x-3000=0 equation:

2x^2+95x-3000=0

a = 2; b = 95; c = -3000;
Δ = b2-4ac
Δ = 952-4·2·(-3000)
Δ = 33025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{33025}=\sqrt{25*1321}=\sqrt{25}*\sqrt{1321}=5\sqrt{1321}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-5\sqrt{1321}}{2*2}=\frac{-95-5\sqrt{1321}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+5\sqrt{1321}}{2*2}=\frac{-95+5\sqrt{1321}}{4}
$